25 ++ magnitude of transfer function formula 586354-Magnitude transfer function calculation

 2,411 712 The transfer function you are starting with is a complex valued function The magnitude is the square root of the sum of the squares of the real part and the imaginary part

Magnitude transfer function calculation-Transfer function is H(s)= b k s k k=0 ∑2 a k s k k=0 ∑ 2 = b 2 s 2b 1 sb 0 a 2 s 10 = 3s2 52 The frequency response is H(jω)= 3(jω)2 (jω)2j5ω2 Magnitude and phase of frequency response I am given the transfer function H(s) = 10/(s(s^2 80s 400)) where s = jω j is the imaginary unit i and I am trying to get it into its magnitude and phase components The Attempt

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Formula Used Magnitude of integrator transfer function= 1/((Angular Frequency in Radians/sec*Capacitance*Resistance))Vo/Vi= 1/((ω*C*R))This formula uses 4Variables The magnitude curve can be obtained by the magnitude of the transfer function The phase curve can be obtained by the phase equation of the transfer function Magnitude

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